>Not surprisingly, the exception you should catch is simply TimeoutError:
> try:
> server.sendmail(sender, receivers, msg.as_string())
> except TimeoutError as e:
> print("SMTP could not be contacted: %s" % e)
> finally:
> server.quit()
The error was thrown by another line :S, after putting the TimeoutError it work
OK (with the proper exception line).
I had to apply a WA server = None to avoid the finally " UnboundLocalError:
local variable 'server' referenced before assignment "
server = None
try:
server = smtplib.SMTP('smtp.mail.com') <--- this is where the
exception was happening.
server.set_debuglevel(True) # show communication with the server
server.sendmail(sender, receivers, msg.as_string())
except TimeoutError as e:
print("SMTP could not be access: %s"%e)
pass
finally:
if server:
server.quit()
Joaquin
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