[EMAIL PROTECTED] wrote:
> Can someone explain to me the output of this simple script? I wonder
> why ['test1.txt'] is printed before "files in c:\", and also why None
> shows up?
>
> ________________
> in file test.py:
>
> def main():
>
> print "files in c:\ :%s" % ListFiles("c:\")
>
> def ListFiles(path):
> for root,dirs,files in os.walk(path):
> print files
>
> if __name__ == "__main__":
> main():
>
> ________________
> output:
>
> C:\> python test.py
> ['test1.txt']
> files in c:\ :None
The function ListFiles() is being called first. This produces the
result that will be used to replace the %s of the print statement. In
this case, the return value is None, so nothing is printed.
How to Think Like a Computer Scientist
http://www.ibiblio.org.obp/thinkCSpy/
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