Chris Angelico, 09.05.2014 11:02:
> On Fri, May 9, 2014 at 6:59 PM, Percy Tambunan wrote:
>> Hai, I would like to parse this multiple root element XML
>
> Easy fix might be to wrap it in <root> and </root>, which will give
> you a new root.
ElementTree's XMLParser() can be use efficiently for this. Something like
this should work:
from xml.etree.ElementTree import XMLParser
parser = XMLParser()
parser.feed(b'<root>')
parser.feed(real_input_data)
parser.feed(b'</root>')
root = parser.close()
for subtree in root:
...
Stefan
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