Τη Δευτέρα, 10 Ιουνίου 2013 4:14:33 μ.μ. UTC+3, ο χρήστης Ulrich Eckhardt
έγραψε:
> Am 10.06.2013 12:57, schrieb Νικόλαος Κούρας:
>
> > >Τη Δευτέρα, 10 Ιουνίου 2013 12:40:01 μ.μ. UTC+3, ο χρήστης Ulrich
>
> > Eckhardt έγραψε:
>
> >
>
> > for key in sorted( months.keys() ):
>
> > print('''
>
> > <option value="%s"> %s </option>
>
> > ''' % (months[key], key) )
>
> >
>
> > this in fact works, it sorts the dict by its keys()
>
>
>
> No, it does not sort the dict. Please slow down, relax and take a look
>
> at the documentation of sorted(). You are jumping to conclusions based
>
> on flawed expectations and assumptions, which can only yield garbage in
>
> the end.
it doe ssort the dict at least for keys() why not for values() too?
for key in sorted( months.keys() ):
print('''
<option value="%s"> %s </option>
''' % (months[key], key) )
this in fact works, it sorts the dict by its keys() was mistaken before
but the sorting aint correct because its done alphabetically and not by
integer value.
We need value
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