> >>>> s = 'α'
> >>>> s.encode('utf-8')
> > b'\xce\xb1'
'b' stands for binary right?
b'\xce\xb1' = we are looking at a byte in a hexadecimal format?
if yes how could we see it in binary and decimal represenation?
> > I see that the encoding of this char takes 2 bytes. But why two exactly?
> > How do i calculate how many bits are needed to store this char into bytes?
> Because utf-8 takes 1 to 4 bytes to encode characters
Since 2^8 = 256, utf-8 should store the first 256 chars of unicode charset
using 1 byte.
Also Since 2^16 = 65535, utf-8 should store the first 65535 chars of unicode
charset using 2 bytes and so on.
But i know that this is not the case.
But i dont understand why.
> >>>> s = 'a'
> >>>> s.encode('utf-8')
> > b'a'
> utf-8 takes ASCII as it is, as 1 byte. They are the same
EBCDIC and ASCII and Unicode are charactet sets, correct?
iso-8859-1, iso-8859-7, utf-8, utf-16, utf-32 and so on are encoding methods,
right?
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