On Sat, Jun 8, 2013 at 12:32 PM, Tim Chase
<[email protected]> wrote:
> def calculate(params):
> a = b = 0
> if some_calculation(params):
> a += 1
> if other_calculation(params):
> b += 1
> return (a, b)
>
> alpha = beta = 0
> temp_a, temp_b = calculate(...)
> alpha += temp_a
> beta += temp_b
>
> Is there a better way to do this without holding each temporary
> result before using it to increment?
Can you pass the function a list with the appropriate values in them,
and have it return them via that?
def calculate(params, sums):
if some_calculation(params):
sums[0] += 1
if other_calculation(params):
sums[1] += 1
sums = [0, 0]
calculate(..., sums)
Or use a dictionary if you'd rather they have names, either way.
ChrisA
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