Hi
I want something to achieve like this :-
def random_number(id): # I am passing it from request
# do something
return random_number
Output
random_number(5)
AXR670
One input that is a number in return you are getting 6 digit alphanumeric
string.
I tried this
s = '%06d' % random.randint(0, 999999)
it gives : '192862' (a string )
Thanks in advance.
On Mon, Mar 26, 2012 at 11:47 AM, Daniel da Silva <[email protected]> wrote:
> If you want it as an int:
> random.randint(100000, 999999)
>
> Or as a string:
> s = '%06d' % random.randint(0, 999999)
>
>
>
> On Mon, Mar 26, 2012 at 2:08 AM, Nikhil Verma <[email protected]>wrote:
>
>> Hi All
>>
>> How can we generate a 6 digit random number from a given number ?
>>
>> eg:-
>>
>> def number_generator(id):
>> random.randint(id,999999)
>>
>> When i am using this it is sometimes giving me five digit and sometimes 6
>> . I want to avoid encryption . Can i have alphanumeric 6 digit random
>> number from this .
>>
>> Thanks in advance
>>
>> --
>> Regards
>> Nikhil Verma
>> +91-958-273-3156
>>
>>
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>>
>>
>
--
Regards
Nikhil Verma
+91-958-273-3156
--
http://mail.python.org/mailman/listinfo/python-list
