Hi,
I'm trying to launch my python program with another process name than
"python.exe".
In order to do that I'm trying to use the os.execvp function :
os.execvp("./Launch.py", ["ProcessName"])
Launch.py is the file that Launch the program and ProcessName is
the ... Process Name ^^
I get this error : OSError : [Errno 8] Exec format error.
I searched and found many solutions like : os.execvp("./Launch.py",
["./Launch.py","ProcessName"]), but nothing worked so far.
Can you help me plz ?
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