In article <[email protected]>,
Mathias Lafeldt <[email protected]> wrote:
> According to [1], there're more Exceptions to test for:
>
> try:
> int(s)
> return True
> except (TypeError, ValueError, OverflowError): # int conversion failed
> return False
I don't think I would catch TypeError here. It kind of depends on how
isInt() is defined. Is it:
def isInt(s):
"Return True if s is a string representing an integer"
or is it:
def isInt(s):
"Return True if s (which must be a string) represents an integer"
If the latter, then passing a non-string violates the contract, and the
function should raise TypeError. If the former, then you could make
some argument for catching the TypeError and returning False, but I
think the second version is what most people have in mind for isInt().
Can you even get an OverflowError any more in a modern Python?
>>>
int('99999999999999999999999999999999999999999999999999999999999999999')
99999999999999999999999999999999999999999999999999999999999999999L
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