On 4/2/2010 6:21 AM, Shashwat Anand wrote:
>>> s = 'si_pos_99_rep_1_0.ita'
>>> res = tuple(re.split(r'(\d+)', s))
>>> res
('si_pos_', '99', '_rep_', '1', '_', '0', '.ita')
This solves the core of the problem, but is not quite there ;-).
Thomas requested conversion of int literals to ints, which is easy:
import re
s = 'si_pos_99_rep_1_0.ita'
res = re.split(r'(\d+)', s)
for i,s in enumerate(res):
try: res[i] = int(s)
except: pass
res = tuple(res)
print(res)
('si_pos_', 99, '_rep_', 1, '_', 0, '.ita')
Terry Jan Reedy
On Fri, Apr 2, 2010 at 3:42 PM, Thomas Heller <[email protected]
<mailto:[email protected]>> wrote:
Maybe I'm just lazy, but what is the fastest way to convert a string
into a tuple containing character sequences and integer numbers,
like this:
'si_pos_99_rep_1_0.ita' -> ('si_pos_', 99, '_rep_', 1, '_', 0, '.ita')
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