On Sun, 2010-02-21 at 13:17 +1100, Lie Ryan wrote: > On 02/21/10 12:02, Stef Mientki wrote: > > On 21-02-2010 01:21, Lie Ryan wrote: > >>> On Sun, Feb 21, 2010 at 12:52 AM, Stef Mientki > <[email protected]> wrote: > >>> > >>>> hello, > >>>> > >>>> I would like my program to continue on the next line after an uncaught > >>>> exception, > >>>> is that possible ? > >>>> > >>>> thanks > >>>> Stef Mientki > >>>> > >>>> > >> That reminds me of VB's "On Error Resume Next" > >> > > I think that's what I'm after ... > > A much better approach is to use callbacks, the callbacks determines > whether to raise an exception or continue execution: > > def handler(e): > if datetime.datetime.now() >= datetime.datetime(2012, 12, 21): > raise Exception('The world has ended') > # else: ignore, it's fine > > def add_ten_error_if_zero(args, handler): > if args == 0: > handler(args) > return args + 10 > > print add_ten_error_if_zero(0, handler) > print add_ten_error_if_zero(10, handler) > print add_ten_error_if_zero(0, lambda e: None) # always succeeds
Or if you don't like having to explicitly manage callbacks, you can try
the "withrestart" module:
http://pypi.python.org/pypi/withrestart/
It tries to pinch some of the good ideas from Common Lisp's
error-handling system.
from withrestart import *
def add_ten_error_if_zero(n):
# This gives calling code the option to ignore
# the error, or raise a different one.
with restarts(skip,raise_error):
if n == 0:
raise ValueError
return n + 10
# This will raise ValueError
print add_ten_error_if_zero(0)
# This will print 10
with Handler(ValueError,"skip"):
print add_ten_error_if_zero(0)
# This will exit the python interpreter
with Handler(ValueError,"raise_error",SystemExit):
print add_ten_error_if_zero(0)
Cheers,
Ryan
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Ryan Kelly
http://www.rfk.id.au | This message is digitally signed. Please visit
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