Michal Ostrowski <[email protected]> writes:
> def MakeLambdaBad():
> a = []
> for x in [1,2]:
> a.append(lambda q: x + q)
> return a
The problem here is that x is a free variable in the lambdas that you
put in a. When you actually evaluate those lambdas, they use whatever
the value of x happens to be at that time. The cure is:
for x in [1,2]:
a.append(lambda q, x=x: x + q)
This creates an additional binding inside the lambda, that captures
the value of the loop index when the lambda is made.
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