On 2009-09-24 14:40 PM, kj wrote:
The docs for divmod include the following:
divmod(a, b)
...For floating point numbers the result is (q, a % b), where q
is usually math.floor(a / b) but may be 1 less than that. ...
I know that floating point math can sometimes produce "unexpected"
results, so the above caveat is not entirely surprising. Still,
I would find it helpful to see a specific example where
divmod(a, b)[0] is equal to math.floor(a/b)-1. Does anybody know
one?
In [21]: a = 10.0
In [22]: b = 10.0 / 3.0
In [24]: divmod(a, b)[0]
Out[24]: 2.0
In [25]: math.floor(a / b) - 1.0
Out[25]: 2.0
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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