On Mon, Dec 22, 2008 at 10:27 AM, Michiel Overtoom <[email protected]> wrote:
> On Monday 22 December 2008 03:23:03 Steven Woody wrote:
>
>> 2. char buf[] = {0x11, 0x22, 0x33, ... }
>>
>> What's the equivalent representation for above in Python?
>
>>>> buf="\x11\x22\33"
>>>> for b in buf: print ord(b)
> ...
> 17
> 34
> 27
>>>>
>
Hi, Michiel
I thing "\x11\x22\x33" in python is not the {0x11, 0x22, 0x33} in C.
Since, a string in python is immutable, I can _not_ do something like:
b[1] = "\x55".
And, how about char buf[200] in my original question? The intension
is to allocate 200 undefined bytes in memory. Thanks.
Regards,
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