En Sun, 17 Aug 2008 21:57:46 -0300, Patrol Sun <[EMAIL PROTECTED]> escribió:
> Of course We needn't 100 levels,but I use the exec function can concise the
> code. See the attachment.
Just a note on the attached code:
def isPro52Num(n):
s=[]
for i in range(1,7):
s.append(str(i*n))
for i in s[0]:
ll = len(string.join(string.split(s[0],i),''))
for j in range(1,6):
if ll!=len(string.join(string.split(s[j],i),'')):
return False
return True
The functions in the string module have been deprecated ages ago in favor of
the corresponding string methods.
In this expression: len(string.join(string.split(s[0],i),'')) if you want to
get "the number of digits in s[0] that are not i" I think it's way faster (and
more clear) to do len(s[0])-s[0].count(i) instead of creating two lists just to
throw them away.
--
Gabriel Genellina
--
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