"Adam W." <[EMAIL PROTECTED]> writes:
> I am using the xml.sax package, and I'm running into a little
> problem. When I use the parse(url, ContentHandler()) method, I don't
> know what parse() is naming the instance of ContentHandler.
I'm not sure what you're asking. Why do you need to know the internal
name for that parameter?
> I have a sub-class of ContentHandler make a dictionary of what it
> parses, but the problem is I don't know the name of instance for me
> to get at it. The only way I have gotten at my dict is to declare it
> a global value, and I know that is not the right way to do it.
Perhaps this::
handler = ContentHandler()
result = parse(url, handler)
--
\ "All my life I've had one dream: to achieve my many goals." -- |
`\ Homer, _The Simpsons_ |
_o__) |
Ben Finney
--
http://mail.python.org/mailman/listinfo/python-list