On Wed, 2008-02-13 at 07:31 -0800, [EMAIL PROTECTED] wrote:
> return re.match("^1?$|^(11+?)\1+$", convert)
That needs to be either
return re.match(r"^1?$|^(11+?)\1+$", convert)
or
return re.match("^1?$|^(11+?)\\1+$", convert)
in order to prevent "\1" from being read as "\x01".
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Carsten Haese
http://informixdb.sourceforge.net
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