"Astan Chee" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
> I have a html text stored as a string. Now I want to go through this
> string and find all 6 digit numbers and make links from them.
> Im using re.sub and for some reason its not picking up the previously
> matched condition. Am I doing something wrong? This is what my code looks
> like:
> htmlStr = re.sub('(?P<id>\d{6})','<a
> href=\"http://linky.com/(?P=id).html\">(?P=id)</a>',htmlStr)
> It seems that it replaces it alright, but it replaces it literally. Am I
> not escaping certain characters?
> Thanks again for the help.
> Cheers
>
> Animal Logic
> http://www.animallogic.com
>
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See the help for re.sub: "Backreferences, such as "\6", are replaced with
the substring matched by group 6 in the pattern."
This should work:
htmlStr = re.sub('(?P<id>\d{6})','<a
href="http://linky.com/\\1.html";>\\1</a>',htmlStr)
--Mark
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