Steven D'Aprano <[EMAIL PROTECTED]> writes:
> On Tue, 18 Dec 2007 21:13:14 +0100, Hrvoje Niksic wrote:
>
>> Each object takes 36 bytes itself: 4 bytes refcount + 4 bytes type ptr +
>> 4 bytes dict ptr + 4 bytes weakptr + 12 bytes gc overhead. That's not
>> counting malloc overhead, which should be low since objects aren't
>> malloced individually. Each object requires a dict, which consumes
>> additional 52 bytes of memory (40 bytes for the dict struct plus 12 for
>> gc). That's 88 bytes per object, not counting malloc overhead.
>
> And let's not forget that if you're running on a 64-bit system, you
> can double the size of every pointer.
And of Py_ssize_t's, longs, ints with padding (placed between two
pointers). Also note the price of 8-byte struct alignment.
> Is there a canonical list of how much memory Python objects take up?
> Or a canonical algorithm?
>
> Or failing either of those, a good heuristic?
For built-in types, you need to look at the code of each individual
object. For user types, you can approximate by calculations such as
the above.
>> Then there's string allocation: your average string is 6 chars
>> long; add to that one additional char for the terminating zero.
>
> Are you sure about that? If Python strings are zero terminated, how
> does Python deal with this?
>
>>>> 'a\0string'[1]
> '\x00'
Python strings are zero-terminated so the pointer to string's data can
be passed to the various C APIs (this is standard practice, C++
strings do it too.) Python doesn't rely on zero termination to
calculate string length. So len('a\0string') will do the right thing,
but the string will internally store 'a\0string\0'.
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