On Aug 4, 5:33 pm, Paddy <[EMAIL PROTECTED]> wrote:
> On Aug 4, 4:18 pm, Paddy <[EMAIL PROTECTED]> wrote:
>
>
>
> > On Aug 2, 10:47 pm, Stef Mientki <[EMAIL PROTECTED]>
> > wrote:
>
> > > hello,
>
> > > I discovered that boolean evaluation in Python is done "fast"
> > > (as soon as the condition is ok, the rest of the expression is ignored).
>
> > > Is this standard behavior or is there a compiler switch to turn it on/off
> > > ?
>
> > > thanks,
> > > Stef Mientki
>
> > The following program shows a(clumsy)? way to defeat the short-
> > circuiting:
>
> > def f(x):
> > print "f(%s)=%s" % ('x',x),
> > return x
> > def g(x):
> > print "g(%s)=%s" % ('x',x),
> > return x
>
> > print "\nShort circuit"
> > for i in (True, False):
> > for j in (True, False):
> > print i,j,":", f(i) and g(j)
>
> > print "\nShort circuit defeated"
> > for i in (True, False):
> > for j in (True, False):
> > print i,j,":", g(j) if f(i) else (g(j) and False)
>
> > The output is:
>
> > Short circuit
> > True True : f(x)=True g(x)=True True
> > True False : f(x)=True g(x)=False False
> > False True : f(x)=False False
> > False False : f(x)=False False
>
> > Short circuit defeated
> > True True : f(x)=True g(x)=True True
> > True False : f(x)=True g(x)=False False
> > False True : f(x)=False g(x)=True False
> > False False : f(x)=False g(x)=False False
>
> > - Paddy.
>
> And here are the bits for boolean OR:
>
> print "\n\nShort circuit: OR"
> for i in (True, False):
> for j in (True, False):
> print i,j,":", f(i) or g(j)
>
> print "\nShort circuit defeated: OR"
> for i in (True, False):
> for j in (True, False):
> print i,j,":", (g(j) or True) if f(i) else g(j)
>
> - Paddy.
Dumb!
Use & and |
Gosh That port last night was good ;-)
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