def f():
a = 12
def g():
global a
if a < 14:
a=13
g()
return aprint f() This function raises an error. Is there any way to access the a in f() from inside g(). I could find few past discussions on this subject, I could not find the simple answer whether it is possible to do this reference. - Suresh -- http://mail.python.org/mailman/listinfo/python-list
