import datetime
def first_day_of_next_month( year, month ):
"""returns the first day of the next month
>>> first_day_of_next_month(2007,5)
datetime.datetime(2007, 6, 1, 0, 0)
>>> first_day_of_next_month(2007,12)
datetime.datetime(2008, 1, 1, 0, 0)
"""
oneday = datetime.timedelta(days=1)
day = datetime.datetime(year, month, 1)
if day.day == 1:
day += oneday
while day.day != 1:
day += oneday
return day
from time import mktime
def secondsInMonth(year, month):
s1 = mktime((year,month,1,0,0,0,0,0,-1))
day = first_day_of_next_month(year, month)
year = day.year
month = day.month
s2 = mktime((year,month+1,1,0,0,0,0,0,-1))
return s2-s1
year = 2007
month = 2
print secondsInMonth(year, month)
[EMAIL PROTECTED] wrote:
Matt> from time import mktime
Matt> def secondsInMonth(year, month):
Matt> s1 = mktime((year,month,1,0,0,0,0,0,-1))
Matt> s2 = mktime((year,month+1,1,0,0,0,0,0,-1))
Matt> return s2-s1
Probably won't work if month==12. ;-)
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Shane Geiger
IT Director
National Council on Economic Education
[EMAIL PROTECTED] | 402-438-8958 | http://www.ncee.net
Leading the Campaign for Economic and Financial Literacy
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org:National Council on Economic Education (NCEE)
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email;internet:[EMAIL PROTECTED]
title:IT Director
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