[EMAIL PROTECTED] wrote:
> A couple of times recently I've come across this problem: I have a
> large list to sort and I need to the the "key=function" argument to
> sort appropriately. But I actually have the key mapping in a big
> dictionary.
Is this what you mean? I suppose the lambda is an "intermediary
function" ... but meh...
l = ['bob', 'dog', 'cat', 'apple']
d = {'bob': 7, 'dog': 0, 'cat': 14, 'apple': 3}
l.sort(lambda x,y: d[x] - d[y])
print l
['dog', 'apple', 'bob', 'cat']
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