Isn't yield like a return?
A return in a list/dict/set comprehension makes no sense to me.
So, +1 on SyntaxError from me too.
Cheers.
On 22.11.2017 21:29, David Mertz wrote:
Inasmuch as I get to opine, I'm +1 on SyntaxError. There is no
behavior for that spelling that I would find intuitive or easy to
explain to students. And as far as I can tell, the ONLY time anything
has ever been spelled that way is in comments saying "look at this
weird edge case behavior in Python."
On Nov 22, 2017 10:57 AM, "Jelle Zijlstra" <jelle.zijls...@gmail.com
<mailto:jelle.zijls...@gmail.com>> wrote:
2017-11-22 9:58 GMT-08:00 Guido van Rossum <gu...@python.org
<mailto:gu...@python.org>>:
Wow, 44 messages in 4 hours. That must be some kind of record.
If/when there's an action item, can someone summarize for me?
The main disagreement seems to be about what this code should do:
g = [(yield i) for i in range(3)]
Currently, this makes `g` into a generator, not a list. Everybody
seems to agree this is nonintuitive and should be changed.
One proposal is to make it so `g` gets assigned a list, and the
`yield` happens in the enclosing scope (so the enclosing function
would have to be a generator). This was the way things worked in
Python 2, I believe.
Another proposal is to make this code a syntax error, because it's
confusing either way. (For what it's worth, that would be my
preference.)
There is related discussion about the semantics of list
comprehensions versus calling list() on a generator expression,
and of async semantics, but I don't think there's any clear point
of action there.
--
--Guido van Rossum (python.org/~guido
<http://python.org/%7Eguido>)
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