Michael Walter wrote:
Yepyep, but *how* you declare types now? Can you quickly type the function
def f(x): x.read()? without needing an interface interface x_of_f: def
read(): pass or a decorator like @foo(x.read)? I've no idea what you
mean, really :o)
Why would something like
def f(x):
x.read()
do any type checking at all?
Cheers,
Nick.
--
Nick Coghlan | [EMAIL PROTECTED] | Brisbane, Australia
---------------------------------------------------------------
http://boredomandlaziness.skystorm.net
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