Dennis Sweeney <[email protected]> added the comment:
The help text says this:
>>> help(list.index)
Help on method_descriptor:
index(self, value, start=0, stop=9223372036854775807, /)
Return first index of value.
Raises ValueError if the value is not present.
Emphasis on *first* index. Example:
>>> L = [0, 10, 20, 33, 0, 10]
>>> L.index(10)
1
>>> L[5]
10
>>> L.index(L[5]) # the same meaning as L.index(10)
1
In your code, when elm has the value 1, it's just the value 1; there's no extra
information carried along about where that 1 came from. If elm == 1, then
my_list.index(elm) means the same as my_list.index(1).
I'd suggest taking any further questions to either StackOverflow or
https://discuss.python.org/c/users/
Thanks for the concern, but I'm closing this as "not a bug". Changing this
behavior now would be backwards-incompatible and break lots of people's code.
----------
nosy: +Dennis Sweeney
resolution: -> not a bug
stage: -> resolved
status: open -> closed
_______________________________________
Python tracker <[email protected]>
<https://bugs.python.org/issue47094>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
