New submission from Dennis Sweeney <[email protected]>:
It seems that `.join` methods typically return the type of the separator on
which they are called:
>>> bytearray(b" ").join([b"a", b"b"])
bytearray(b'a b')
>>> b" ".join([bytearray(b"a"), bytearray(b"b")])
b'a b'
This is broken in UserString.join:
>>> from collections import UserString as US
>>> x = US(" ").join(["a", "b"])
>>> type(x)
<class 'str'>
Furthermore, this method cannot even accept UserStrings from the iterable:
>>> US(" ").join([US("a"), US("b")])
Traceback (most recent call last):
...
TypeError: sequence item 0: expected str instance, UserString found.
I can submit a PR to fix this.
----------
components: Library (Lib)
messages: 363995
nosy: Dennis Sweeney
priority: normal
severity: normal
status: open
title: UserString.join should return UserString
type: behavior
versions: Python 3.9
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Python tracker <[email protected]>
<https://bugs.python.org/issue39944>
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