Ronald Oussoren <[email protected]> added the comment:
>From the zip file, the "bug" is:
# ----
def parent_function2( argument1 ):
def child_function():
print( argument1 )
if False:
argument1 = None # Same function but with fake
assignment
return child_function
# ----
This doesn't work because "argument1" is a local variable in the nested
function, and not the same as "argument1" in the outer function. This is
expected behavior.
The workaround from the same zipfile is to assign the argument of the outer
function to a local variable in that outer function, that way the value can be
used in the inner function. That is a valid way to deal with this, although I'd
use a different name in the inner function.
The "nonlocal" keyword in Python 3 might be useful here, but that depends on
whether or not you want changes to "argument1" in the inner function to affect
the value of "argument1" in the outer function.
All in all I don't think there's a bug in Python here.
----------
nosy: +ronaldoussoren
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