Peter Otten added the comment:
Your code relies on the assumption that when the lambda is invoked the global t
is still bound to the Thread instance you are starting. It seems that this is
not always the case, and I don't see why it should be guaranteed either.
I don't know whether it's a good idea to store per-thread data in the Thread
instance (have a look at threading.local()), but
def start_thread():
t = Thread(target=lambda: f(t))
t.obj = [0]
t.start()
for _ in range(n_threads):
start_thread()
will at least avoid the global.
----------
nosy: +peter.otten
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<http://bugs.python.org/issue27468>
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