New submission from Keita Kita:
On Python 3.4, input() does not use wrapped sys.stdout. For example, the
following script should print "Wrapped stdout" by print() and input() because
sys.stdout is replaced with Writer object.
--------
import io
import sys
class Writer:
def __getattr__(self, name):
return getattr(sys.__stdout__, name)
def write(self, data):
if data != '\n':
sys.__stdout__.write('Wrapped stdout\n')
def fileno():
raise OSError()
sys.stdout = Writer()
print('print')
input('input')
------
But the script does not print "Wrapped stdout" as prompt of input(). The script
prints the following.
-----
Wrapped stdout
input
----
Although, when sys.stdin is also wrapped, input() will use sys.stdout for
prompt. For example, the following script prints "Wrapped stdout" by print()
and input().
----
import io
import sys
class Writer:
def __getattr__(self, name):
return getattr(sys.__stdout__, name)
def write(self, data):
if data != '\n':
sys.__stdout__.write('Wrapped stdout\n')
def fileno():
raise OSError()
class Reader:
def __getattr__(self, name):
return getattr(sys.__stdin__, name)
def read(self, size):
return sys.__stdin__.read(size)
def fileno():
raise OSError()
sys.stdout = Writer()
sys.stdin = Reader()
print('print')
input('input')
----
The script prints the following.
-----
Wrapped stdout
Wrapped stdout
----
----------
components: Interpreter Core
messages: 244949
nosy: Keita Kita
priority: normal
severity: normal
status: open
title: input() uses sys.__stdout__ instead of sys.stdout for prompt
type: behavior
versions: Python 3.4
_______________________________________
Python tracker <[email protected]>
<http://bugs.python.org/issue24402>
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