Walter Dörwald added the comment:
The following doesn't work::
import inspect
def foo(*args, **kwargs):
return (args, kwargs)
# Code from
https://docs.python.org/3/library/inspect.html#inspect.BoundArguments.arguments
to fill in the defaults
sig = inspect.signature(foo)
ba = sig.bind()
for param in sig.parameters.values():
if param.name not in ba.arguments:
ba.arguments[param.name] = param.default
print(foo(*ba.args, **ba.kwargs))
instead it gives the following traceback::
Traceback (most recent call last):
File "sig_test.py", line 16, in <module>
print(foo(*ba.args, **ba.kwargs))
File "/Users/walter/.local/lib/python3.4/inspect.py", line 2246, in args
args.extend(arg)
TypeError: 'type' object is not iterable
In my use case there isn't a call to a function implemented in Python. Instead
I'm implementing a templating languages that supports defining a signature for
a template. Calling the template binds the arguments and inside the template
the variables simply are a dictionary.
I.e. define the template like this:
t = Template("<?print a+b?>", signature="a, b=23")
Then you can call it like this:
t(17)
and inside the template the variables will be {"a": 17, "b": 23}.
The signature argument in the Template constructor will be parsed into an
inspect.Signature object and I'd like to use Signature.bind() to get the final
variables dictionary.
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Python tracker <[email protected]>
<http://bugs.python.org/issue22998>
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