Ronald Oussoren added the comment:
This is a side effect to the way the in place operators work.
Basically "a[0] += [3]" is evaluated as:
a[0] = a[0].__iadd__([3])
The call to __iadd__ succeeds, which is why the list is updated, but you get an
exception when the interpreter tries to update item 0 of the tuple.
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nosy: +ronaldoussoren
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<http://bugs.python.org/issue17973>
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