Mark Dickinson <[email protected]> added the comment:
Thanks for the report. Yes, this is expected. Dictionary membership is based
on equality of keys. Since True and 1 are equal, only one of them can be
present in a dictionary at a time (and a key lookup works with either).
>>> x = {0: 'bar'}
>>> x[0]
'bar'
>>> x[False]
'bar'
>>> x[0.0]
'bar'
>>> 0 == False
True
----------
nosy: +mark.dickinson
resolution: -> invalid
status: open -> closed
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Python tracker <[email protected]>
<http://bugs.python.org/issue14898>
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