Hello,
I am creating a dialog in a callback function. Is there a way to make
the dialog window disappear before the callback function returns?
I do not care if the main window keeps unresponsive, I just want the
dialog to disappear.
Here is a small sample script to demonstrate what I mean:
#!/usr/bin/env python
import pygtk
import gtk
import time
class View(gtk.Window):
def __init__(self):
super(View, self).__init__(gtk.WINDOW_TOPLEVEL)
self.connect("delete_event", lambda *a: False)
self.connect("destroy", gtk.main_quit)
self.set_border_width(10)
self.set_title('Look at this')
button = gtk.Button("Do stuff")
button.connect('clicked', self.do_stuff)
self.add(button)
self.show_all()
def do_stuff(self, *a):
if not self.yes_or_cancel_dialog('Question', 'Really do stuff? (may take a while)'):
return
# TODO: Call mysterious function that makes the dialog disappear
# Do something
time.sleep(5)
def yes_or_cancel_dialog(self, title, text):
dialog = gtk.Dialog(title, self, gtk.DIALOG_MODAL,
(gtk.STOCK_CANCEL, gtk.RESPONSE_REJECT,
gtk.STOCK_OK, gtk.RESPONSE_ACCEPT))
label = gtk.Label(text)
label.show()
dialog.vbox.pack_start(label)
response = dialog.run()
dialog.destroy()
return response == gtk.RESPONSE_ACCEPT
if __name__ == '__main__':
view = View()
gtk.main()
I would like to have the dialog window disappear *before* the
time.sleep() in do_stuff() finishes. Is that possible?
Best,
-Nikolaus
--
»Time flies like an arrow, fruit flies like a Banana.«
PGP fingerprint: 5B93 61F8 4EA2 E279 ABF6 02CF A9AD B7F8 AE4E 425C
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