I'm sorry, what I meant was this.superclass In Prototype's class
implementation you can see that if you provide a parent-class in prototype's
Class.Create-Method, that class will be referenced as superclass in the
class you are creating:
function create() {
var parent = null, properties = $A(arguments);
if (Object.isFunction(properties[0]))
parent = properties.shift();
// ...
klass.superclass = parent;
// ...
return klass;
}
why not just use this.superclass.method in the subclass?
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