Hello, Thanks for responding in case I want that if the consumption of messages in the topic in the last 5 minutes is 0 and the production of messages is greater than 1 in the topic, then the group of consumers is not consuming messages and I wanted to return which groups and topics these would be Em sexta-feira, 19 de abril de 2024 às 15:36:44 UTC-3, Brian Candler escreveu:
> Maybe what you're trying to do is: > > sum by (consumergroup, topic) > (rate(kafka_consumergroup_current_offset[5m]) * 60) == 0 > unless sum by (topic) (rate(kafka_consumergroup_current_offset[5m]) * 60) > < 1 > > That is: alert on any combination of (consumergroup,topic) where the > 5-minute rate of consumption is zero, unless the rate for that topic across > all consumers is less than 1 per minute. > > As far as I can tell, kafka_consumergroup_current_offset is a counter, and > therefore you should use either rate() or increase(). The only difference > is that rate(foo[5m]) gives the increase per second, while > increase(foo[5m]) gives the increase per 5 minutes. > > Hence: > rate(kafka_consumergroup_current_offset[5m]) * 60 > increase(kafka_consumergroup_current_offset[5m]) / 5 > should both be the same, giving the per-minute increase. > > On Friday 19 April 2024 at 18:30:21 UTC+1 Brian Candler wrote: > >> Sorry, first link was wrong. >> https://groups.google.com/g/prometheus-users/c/IeW_3nyGkR0/m/unto0oGQAQAJ >> https://groups.google.com/g/prometheus-users/c/83pEAX44L3M/m/E20UmVJyBQAJ >> >> On Friday 19 April 2024 at 18:28:29 UTC+1 Brian Candler wrote: >> >>> Can you give examples of the metrics in question, and what conditions >>> you're trying to check for? >>> >>> Looking at your specific PromQL query: Firstly, in my experience, it's >>> very unusual in Prometheus queries to use ==bool or >bool, and in this >>> specific case definitely seems to be wrong. >>> >>> Secondly, you won't be able to join the LH and RH sides of your >>> expression with "and" unless either they have exactly the same label sets, >>> or you modify your condition using "and on (...)" or "and ignoring (...)". >>> >>> "and" is a vector intersection operator, where the result vector >>> includes a value if the labels match, and the value is taken from the LHS, >>> and that means it doesn't combine the values like you might be used to in >>> other programming languages. For example, >>> >>> vector(0) and vector(1) => value is 0 >>> vector(1) and vector(0) => value is 1 >>> vector(42) and vector(99) => value is 42 >>> >>> This is as described in the documentation >>> <https://prometheus.io/docs/prometheus/latest/querying/operators/#logical-set-binary-operators> >>> : >>> >>> vector1 and vector2 results in a vector consisting of the elements of >>> vector1 for which there are elements in vector2 with exactly matching >>> label sets. Other elements are dropped. The metric name and values are >>> carried over from the left-hand side vector. >>> >>> PromQL alerts on the presence of values, and in PromQL you need to think >>> in terms of "what (labelled) values are present or absent in this vector", >>> using the "and/unless" operators to suppress elements in the result vector, >>> and the "or" operator to add additional elements to the result vector. >>> >>> Maybe these explanations help: >>> https://groups.google.com/g/prometheus-users/c/IeW_3nyGkR0/m/NH2_CRPaAQAJ >>> https://groups.google.com/g/prometheus-users/c/83pEAX44L3M/m/E20UmVJyBQAJ >>> >>> On Friday 19 April 2024 at 16:31:23 UTC+1 Robson Jose wrote: >>> >>>> Good afternoon, I would like to know if it is possible to do this >>>> query, the value that should return is applications with a value of 0 in >>>> the first query and greater than one in the 2nd >>>> >>>> ( >>>> sum by (consumergroup, topic) >>>> (delta(kafka_consumergroup_current_offset{}[5m])/5) ==bool 0 >>>> ) >>>> and ( >>>> sum by (topic) (delta(kafka_consumergroup_current_offset{}[5m])/5) >>>> >bool 1 >>>> ) >>>> >>> -- You received this message because you are subscribed to the Google Groups "Prometheus Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/prometheus-users/95e9a932-ded6-4396-8e9a-3a0393cb41fdn%40googlegroups.com.
