Paul,
An implementation of the NumberAtEnd method using Regular Expressions
(changed the pattern to give a bit more robustness):
m.acid1 = "Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid (2.13)"
m.acid2 = "Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid"
? NumberAtEnd(m.acid1) && 2.13
? NumberAtEnd(m.acid2) && FAIL
FUNCTION NumberAtEnd (Test AS String) AS String
LOCAL Regx AS VBScript_RegExp_55.RegExp
LOCAL Matches AS VBScript_RegExp_55.MatchCollection
LOCAL Result AS String
m.Regx = CREATEOBJECT("VBScript.RegExp")
m.Regx.Pattern = "(\(([0-9]+(\" + SET("Point") + "[0-9]+)?)\))$"
m.Matches = m.Regx.Execute(m.Test)
IF m.Matches.Count == 1
m.Result = m.Matches.Item(0).SubMatches.item(1)
ELSE
m.Result = "FAIL"
ENDIF
RETURN m.Result
ENDFUNC
On Mon, Dec 12, 2022 at 1:10 PM Paul Newton <[email protected]>
wrote:
> Hi all
>
> I've been very quiet for a while so I thought it was about time I chimed
> in again. I have come across the use of a regex expression in another
> language which works like this:
>
> acid1 = "Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid (2.13)"
> acid2 = "Methionine = (S)-2-amino-4-(methylsulfanyl)-butanoic acid"
>
> NumberAtEnd:= proc(S::string)
> description
> "Extract a parenthesized number, possibly containing periods, from
> the end of a string":
> local r;
> if StringTools:-RegMatch("\\(([0-9.]*)\\)$", S, r$2) then r else
> FAIL fi
> end proc:
>
> NumberAtEnd(acid1) returns "2.13"
> NumberAtEnd(acid2) returns "FAIL"
>
> How can this be done in VFP? Many thanks
>
> Paul Newton
> ***
>
> *
>
>
>
[excessive quoting removed by server]
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