You da man, Leif.
That did the trick.
Didn't try the output buffering idea. I need to look into that area.
Thanks for illuminating things a bit............
--Noah
----- Original Message -----
From: "Leif K-Brooks" <[EMAIL PROTECTED]>
To: "CF High" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Monday, March 03, 2003 5:01 PM
Subject: Re: [PHP] Populate var with function output string?
> Try adding each output string to a variable, then returning it, like:
>
> function return_string(count) {
> $return = '';
> for ($x = 0; $x < $count; $x++) {
>
> $return.= "<option value=$x> Row $x</option>";
>
> }
> return $return;
>
> }
>
> If you can't do that for some reason, try using output buffering.
> www.php.net/ob-start
>
> CF High wrote:
>
> >Hey all.
> >
> >Is it possible to populate a var with an output string generated by a
> >function? So:
> >
> >*******************************
> >function write_string(count) {
> >
> > for ($x = 0; $x < $count; $x++) {
> >
> > echo "<option value=$x> Row $x</option>";
> >
> > }
> >
> >}
> >
> >$my_string = write_string(5);
> >
> >echo $my_string;
> >*******************************
> >
> >I need $count option elements stored in $my_string. How to make this
happen.
> >
> >Thanks for any ideas,
> >
> >--Noah
> >
> >
> >--
> >
> >
> >
> >
> >
> >
>
> --
> The above message is encrypted with double rot13 encoding. Any
unauthorized attempt to decrypt it will be prosecuted to the full extent of
the law.
>
>
>
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