I would guess you are trying to create an HTML table to display the records.
$Row = The results returned from. mysql_fetch_array().
$Total = count($Row);
$TotalInEachRow = round(($Total/3));
if (($TotalInEachRow * 3) < $Total) {
$TotalInEachRow ++; // Planning for the Remainder items.
}$HTML = "<TABLE>"; // HTML string that holds the table
$ColumnCount = 0; // For knowing the Number of Columns.
for ($C=0; $C<$Total; $C++) {
if ($ColumnCount == 0) {
$HTML .= "<TR>";
}
$HTML .= "<TD>".$Row[$C]["DatabaseFeildName"]."</TD>":
$ColumnCount ++;
if ($ColumnCount == 3) {
$HTML ."</TR>";
$ColumnCount = 0;
}
}if ($ColumnCount > 0) {
for ($C=$ColumnCount; $C<=3; $C++) {
$HTML .= "<TD> </TD>";
}
$HTML .= "</TR>";
}$HTML .= "</TABLE>":
That should do it for you. I typed this code directly into the email so be forwarned about copy and pasting it.
Hope this helped.
Jonathan Pitcher
On Monday, March 3, 2003, at 08:58 AM, Awlad Hussain wrote:
I have a mysql table containing about 100 record, alphabetically ordered.
How would i display them in browser in a 3 columns, doesn't matter how long the rows is as the number of records will grow in the database table.
the records should be in alphabetically order, for example:
aaa bbba ccca aab bbbb cccb aac bbbc cccc aad bbbd cccd
any idea anyone?
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