Re: [PHP] Help with POSTing variable array names from a PHP script please.

Sat, 15 Feb 2003 02:44:30 -0800

Jason

Thanks for your help .

I've implemented you advice. The problem persists in that I'm trying create the following situation:
When the posted action php script runs I want the retrieved $_POST array to contain such information that the action script can find out what checkboxes were clicked and from there the library books to retrieve.
So what do I need to write:
1. for the checkbox line in the driving script, e.g.
type="checkbox" name="???" value ="ON"

2. in the action script, e.g.

$result = $_POST[???];

Mike

---

Jason Wong wrote:

On Saturday 15 February 2003 17:05, Michael Eacott wrote:


<? php

# Show details of BOOKS

# Performing SQL query

$query = "SELECT * FROM `$books` WHERE `title` LIKE '$title' LIMIT 99";
$result = mysql_query($query) or die("Query failed");

$count = 1; $bookslist = "";
while ($rowarray = mysql_fetch_array($result, MYSQL_ASSOC))
{
Your while loop is loop at the wrong place. Look at the HTML source of your page ...

   $booksid = $rowarray["booksid"];
   $title = $rowarray["title"];
   print '<html>';
   print '<head>';
   print '<meta http-equiv="Content-Language" content="en-us">';
   print '<meta http-equiv="Content-Type" content="text/html;
charset=windows-1252">';


[snip]

... these are all repeated for each book. Clearly that's not what you want.
print '<p>Click box get following book retrieved. 
Your loop should start here:


<input
type="checkbox" name="book[1][$booksid]" value ="ON" ><br>';


You've setup a counter ($count) so make use of it:

<input type="checkbox" name="book[$count][$booksid]" value ="ON" >

























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