It is not included because your didn't installed jpeg lib.

GD needs an external lib to work with jpeg, so yes it's an administrator's
work.

--
Regards.
M.CHAILLAN Nicolas
[EMAIL PROTECTED]
www.WorldAKT.com Hébergement de sites internets.

"Sed" <[EMAIL PROTECTED]> a écrit dans le message de news:
000d01c2ceb4$c96f60b0$[EMAIL PROTECTED]
So, why is this function not included in GD like imagecreatefrompng()?
Can this be just bad configuration at my Administrator behalf?

-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 7. febrúar 2003 14:15
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Why is function imagecreatefromjpeg() undefined in
PHP 4.3 when GD is enabled and imagecreatefrompng() id defined? A bug?


You need to install  jpeg-6bftp://ftp.uu.net/graphics/jpeg/ and dd
--with-jpeg-dir=DIR.

--
Regards.
M.CHAILLAN Nicolas
[EMAIL PROTECTED]
www.WorldAKT.com Hébergement de sites internets.

"Sed" <[EMAIL PROTECTED]> a écrit dans le message de news:
000901c2ceb3$90746450$[EMAIL PROTECTED]
> Hi,
>
> Why is function imagecreatefromjpeg() undefined in PHP 4.3 when GD is
> enabled and imagecreatefrompng() id defined?
>
>
>
> Is it a bug? Or?
>
> My ISP config:
>
> System  Linux titan 2.4.18-3 #1 Thu Apr 18 07:37:53 EDT 2002 i686
> Build Date  Jan 24 2003 19:35:29 Configure Command  './configure'
> '--with-mysql' '--with-apxs' '--with-zlib' '--with-bz2' '--with-gd'
> '--with-gettext' '--with-pgsql' Server API  Apache
> Virtual Directory Support  disabled
> Configuration File (php.ini) Path  /usr/local/lib/php.ini
> PHP API  20020918
> PHP Extension  20020429
> Zend Extension  20021010
> Debug Build  no
> Thread Safety  disabled
> Registered PHP Streams  php, http, ftp, compress.bzip2, compress.zlib
>
>
> Regards,
> Sumarlidi E. Dadason
>
> SED - Graphic Design
>
> E-mail: [EMAIL PROTECTED]
> website: www.sed.is
>



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