At 11:57 25.11.2002, Dan Field said:
--------------------[snip]--------------------
>is it doable?
>
>class myClass {
> var $myInt;
>
> // default constructor
> function myClass() {
> }
>
> // overloaded constructor
> function myClass($newInt) {
> $this->myInt = $newInt;
> }
>}
--------------------[snip]--------------------
At least not with PHP 4.2:
<?php
class A {
function A() {
echo "default constructor A()\n";
}
function A($string) {
echo "overloaded constructor A($string)\n";
}
}
$a1 = new A();
$a2 = new A('Test');
?>
Results in:
overloaded constructor A()
overloaded constructor A(Test)
thus bypassing the default constructor and calling the overloaded
constructor both times.
What you might do to distinguish which "overload" has been called:
function A($string=null) {
if (!isset($string))
echo "Default constructor A()\n";
else
echo "Overloaded constructor A($string)\n";
}
Hope this helps,
--
>O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
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