On Saturday 26 October 2002 18:23, James Taylor wrote:
> There's got to be a better way to go about this: I am constantly doing
> mysql queries where I am doing
> a count(), so a sample query would be like this: "select count(*) from
> database". I'm expecting only
> ONE value back exactly, and that's the count results. However, to get this
> data into a variable, i'm
> having to write code like this:
>
> $result = mysql_query("select count(*) from database", $db);
> $myrow = mysql_fetch_row($result);
> $staticvar += $myrow[0];
>
> $staticvar will never be an array, it's just a simple variable storing a
> number. I *could* do it like this:
>
> $result = mysql_query("select * from database", $db);
> $staticvar += mysql_num_rows($result);
>
> However, the mysql query will be much, much slower if I do it like this.
>
> Basically, what I'm asking, is how to do something like:
>
> $staticvar += mysql_fetch_row($result);
>
> I want to eliminate step two, and I don't want to involve any temporary
> arrays when there's always just one
> value. Any suggestions? Thanks a bunch!
You can assign the directly into a variable using something like:
list($count) = mysql_fetch_array($result);
Not sure whether you can do a += into an existing variable though.
Why don't you just stuff the above into a function instead?
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
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