It's just part of the rules. Variables are not evaluated when they are between single quotes, they are between double quotes.
Echo 'This is $var'; Will output that string, literally. Echo "This is $var"; Will take the value of $var, if any, and place it in the string. ---John Holmes... > -----Original Message----- > From: Chuck PUP Payne [mailto:[EMAIL PROTECTED]] > Sent: Sunday, September 22, 2002 11:53 PM > To: [EMAIL PROTECTED] > Cc: PHP General > Subject: Re: [PHP] Help with mail... > > Ok, that work. Why does the ' (quote) not make it work is it because it's > an > array? Any thanks John that got it work. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
