Hello I'm using PHP4 and MySQL on Apache webserver. I have a table valled "liste" with names of some people, and a table called "postnummer" with zip-codes and citynames. My select should join the adress and zip from one table with the cityname from the other table. But my join-line does not work. =:(
My code results in this line: Warning: Supplied argument is not a valid MySQL result resource in /var/www/html/find/resultat.php on line 27 The code is: mysql_select_db("adresser"); $query = ("SELECT fornavn, efternavn, gade, liste.postnummer, postnummer.postbynavn FROM liste left join postnummer on liste.postnummer = postnummer.postnummer WHERE MATCH (fornavn, efternavn) AGAINST ('$search');"); $result = mysql_query($query); while(list( $fornavn, $efternavn, $gade, $postnummer, $postbynavn) = mysql_fetch_row($result)) print("<TR><TD>$fornavn</TD><TD>$efternavn</TD><TD>$gade</TD><TD>$postnummer</TD><TD>$postbynavn</TD></TR>\n"); What is going on? The select is ok if I do not join, but then I'm not able to get the field "postbynavn" from the other table. PLEASE HELP! Henning -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php