Thank you, I figured it out 30 seconds after I posted the question, you were right about the problem.
- Victor > www.argilent.com -----Original Message----- From: Chris Wesley [mailto:[EMAIL PROTECTED]] Sent: Monday, September 02, 2002 4:11 PM To: 'PHP' Cc: Victor Subject: Re: [PHP] help, array values echoed as Array on loop! On Mon, 2 Sep 2002, Victor wrote: > $ID_arr[] = explode(',', $pictures); # make db data into array > This is the string: > 15,16,17,18,19 > > why does it echo as Array? ... because you've created an array ($ID_arr) with an array as the first value (the result of the call to explode()). Take the brackets off $ID_arr, and you'll get what you want. You don't want your array in an array ... you just want an array. $ID_arr = explode(',', $pictures); If you really wanted your array in the array, then loop over $ID_arr[0]. (I doubt that's what you were going for, though.) hth, ~Chris ______________________________________________________________________ Post your free ad now! http://personals.yahoo.ca -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
