<?
$fn = 'test.gif';
echo preg_replace('/(.+?)(\..+?)/', '\1a\2', $fn);?> This script will output 'testa.gif' now how can i make it produce 'test1.gif' ? if i replace the: '\1a\2' with '\11\2' it will understand to replace with occurence number 11 ! How can i escape the 2nd '1' so it is considered as a string an not another number. Elias -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
