Hiya,
You're using single quotes around all your strings,
for variables to be replaced with their values, you must use double quotes.
Try replacing every ' with ".
HTH,
Dw
Sqlcoders.com Dynamic data driven web solutions
----- Original Message -----
From: "Jule Slootbeek" <[EMAIL PROTECTED]>
To: "mysql" <[EMAIL PROTECTED]>; "php-general"
<[EMAIL PROTECTED]>
Sent: June 03 2002 03:09 PM
Subject: [PHP] stupid error, please kick me (and send me a solution)
> Hey guys,
> i'm getting this error with the following sql script using php:
> --error--
> Warning: Supplied argument is not a valid MySQL-Link resource in
> /var/www/phpquiz/register_user.php on line 12
> --error--
>
> --script--
> $link_glob = "mysql_connect('$host_glob', '$un_glob', '$pw_glob')";
> $query = "INSERT INTO user values('0', '$fname', '$lname', '$email',
> '$username', PASSWORD('$password')";
> $result = mysql_db_query('$db_glob', '$query', $link_glob');
> if (!$result) {
> echo "<font size=+1>Your Information could not be entered into the
database,
> Please contact the <a
> href=mailto:$webmaster>webmaster</a>.</font><br><br>" . mysql_errno() .
> ": " . mysql_error() . "<br><br>";
> } else {
> echo "<font size=+1>Your Information has successfully been entered into
the
> database!</font><br>";
>
> --
> Jule Slootbeek
> [EMAIL PROTECTED]
>
> http://blindtheory.cjb.net
>
>
>
> --
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>
>
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