simple..
try this:
echo eval($variablename);
then again why are you eval()ing at all??
why can't you do this:
$var1="var2";
$$var1=13;
echo $var2;
//or perhaps even better:
//echo $$var1;
seems simple enough.. haven't tested but theory is there I think..
HTH
:::::::::::::::::::::::::::::::::::::::::::
: Julien Bonastre [The-Spectrum.org CEO]
: A.K.A. The_RadiX
: [EMAIL PROTECTED]
: ABN: 64 235 749 494
: QUT Student #: 04475739
:::::::::::::::::::::::::::::::::::::::::::
----- Original Message -----
From: "Henry" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, May 19, 2002 12:29 AM
Subject: [PHP] How can I access the value in a variable whos name is in a
string
> Dear All,
>
> $variablename="variable";
> eval("\$".$variablename."=13;");
> echo $variable;
>
> This works fine!! It echoes "13";
>
> But this doesn't ->
>
> echo eval("\"$variablename\"");
>
> Why??
>
>
> Henry
>
>
>
>
> --
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>
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