The more generic approach:
function getNextColour( &$lastIndex, $colourList )
{
return $colourList[(++$lastIndex % count( $colourList ))];
}
$colours = array
(
'#ff0000',
'#00ff00',
'#0000ff'
);
$index = 0;
foreach( $rows as $aRow )
{
echo '<tr bgcolor="'.getNextColour( $index, $colours ).'">'
.$aRow
.'</tr>'."\n";
}
Cheers,
Rob.
-----------------------------------------------------------------------------
Jay Blanchard wrote:
>
> [snip]
> Is there a way for me to do one of the following:
>
> 1) Test to see if $i is an even or odd number?
> 2) Grab more than one line from the database at a time, and just put in two
> table rows at once?
> [/snip]
>
> <?
> $rowcount = 0;
> while($dbrowa = mysql_fetch_object($dbseta)){
> $dbrowb = mysql_fetch_object($dbsetb);
> //change the color of alternating rows
> $rowcount ++;
> if ($rowcount == 1){
> print("<tr bgcolor=\"#FFFF99\">\n");
> }
> elseif ($rowcount <> 1) {
> print("<tr>\n");
> $rowcount = 0;
> }
>
> This way you don't have to know even or odd.
> $rowcount is 0
> $rowcount is set to one and printed in a different color
> $rowcount is set to two, which is not equal to one, so does elseif and is
> set to zero
>
> HTH!
>
> Jay
>
> --
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| Webdeployer - Chief PHP and Java Programmer |
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